x(x-4)-2=x^2-4(x+3)

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Solution for x(x-4)-2=x^2-4(x+3) equation:


Simplifying
x(x + -4) + -2 = x2 + -4(x + 3)

Reorder the terms:
x(-4 + x) + -2 = x2 + -4(x + 3)
(-4 * x + x * x) + -2 = x2 + -4(x + 3)
(-4x + x2) + -2 = x2 + -4(x + 3)

Reorder the terms:
-2 + -4x + x2 = x2 + -4(x + 3)

Reorder the terms:
-2 + -4x + x2 = x2 + -4(3 + x)
-2 + -4x + x2 = x2 + (3 * -4 + x * -4)
-2 + -4x + x2 = x2 + (-12 + -4x)

Reorder the terms:
-2 + -4x + x2 = -12 + -4x + x2

Add '4x' to each side of the equation.
-2 + -4x + 4x + x2 = -12 + -4x + 4x + x2

Combine like terms: -4x + 4x = 0
-2 + 0 + x2 = -12 + -4x + 4x + x2
-2 + x2 = -12 + -4x + 4x + x2

Combine like terms: -4x + 4x = 0
-2 + x2 = -12 + 0 + x2
-2 + x2 = -12 + x2

Add '-1x2' to each side of the equation.
-2 + x2 + -1x2 = -12 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-2 + 0 = -12 + x2 + -1x2
-2 = -12 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-2 = -12 + 0
-2 = -12

Solving
-2 = -12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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